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Q. The de-Broglie wavelength of a neutron in thermal equilibrium with heavy water at a temperature $T$ (Kelvin) and mass $m$, is :

NEETNEET 2017Dual Nature of Radiation and Matter

Solution:

de-Broglie wavelength
$\lambda =\frac{h}{m v}$
$=\frac{h}{\sqrt{2 m( KE )}}$
$=\frac{h}{\sqrt{2 m\left(\frac{3}{2} k T\right)}}$
$\lambda =\frac{h}{\sqrt{3 m k T}}$