The de-Broglie wavelength λ of an electron accelerated through a potential V (in volt) is

Question

The de-Broglie wavelength λ of an electron accelerated through a potential V (in volt) is (A)  (1.227/√V)nm  (B)  (0.1227/√V)nm  (C)  (0.01227/√V)nm  (D)  (0.001227/√V) nm

Tardigrade Admin · Accepted Answer

The de-Broglie wavelength λ =(1.227/√V)nm

Q. The de-Broglie wavelength $λ$ of an electron accelerated through a potential $V$ (in volt) is

$\frac{1.227}{V} nm$

$\frac{0.1227}{V} nm$

$\frac{0.01227}{V} nm$

$\frac{0.001227}{V} nm$

The de-Broglie wavelength
$λ = \frac{1.227}{V} nm$

Q. The de-Broglie wavelength λ of an electron accelerated through a potential V (in volt) is

V​1.227​nm

V​0.1227​nm

V​0.01227​nm

V​0.001227​nm