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Physics
The de-Broglie wavelength λ of an electron accelerated through a potential V (in volt) is
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Q. The de-Broglie wavelength $ \lambda $ of an electron accelerated through a potential $V$ (in volt) is
J & K CET
J & K CET 2011
Dual Nature of Radiation and Matter
A
$ \frac{1.227}{\sqrt{V}}nm $
75%
B
$ \frac{0.1227}{\sqrt{V}}nm $
14%
C
$ \frac{0.01227}{\sqrt{V}}nm $
7%
D
$ \frac{0.001227}{\sqrt{V}} nm $
3%
Solution:
The de-Broglie wavelength
$ \lambda =\frac{1.227}{\sqrt{V}}nm $