Question

The $d-$ orbital involved in $s{p}^{3}d-$ hybridisation is

• A. $d_{x^2-y^2}$
• B. $d_{xy}$
• C. $d_{z^2}$
• D. $d_{zx}$

Answer 1

Answer: (D)

The $d$ - orbital involved in $s{p}^{3}d$ - hybridization is $d_{zx}$.
$s{p}^{3}d$ : one $s+$ three $p\left(ie,p_x,p_y,p_z\right)+$ one $d\left(ie,d_{zx}\right)$