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Question
Chemistry
The d-electron configuration of [Ru(en)3]Cl2 and [ Fe ( H 2 O )6] Cl 2, respectively are:
Q. The d-electron configuration of
[
R
u
(
e
n
)
3
]
C
l
2
and
[
F
e
(
H
2
O
)
6
]
C
l
2
, respectively are:
1901
199
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Coordination Compounds
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A
t
2
g
4
e
g
2
and
t
2
g
6
e
g
0
14%
B
t
2
g
6
e
g
0
and
t
2
g
6
e
g
0
26%
C
t
2
g
6
e
g
0
and
t
2
g
4
e
g
2
54%
D
t
2
g
4
e
g
2
and
t
2
g
4
e
g
2
6%
Solution:
[
R
u
(
e
n
)
3
]
C
l
2
R
u
⇒
4
d
series
en
⇒
chelating ligand
CN
=
6
, octahedral splitting hence large splitting of d-subshell
[
F
e
(
H
2
O
)
6
]
C
l
2
⇒
H
2
O
⇒
Weak filled ligand
F
e
+
2
⇒
[
A
r
]
3
d
6
4
s
0
less splitting
CN
=
6
octahedral splitting