The cylindrical shape of an alkyne is due to

Question

The cylindrical shape of an alkyne is due to (A) three sigma C-C bonds (B) three π C-C bonds (C) two sigma C-C and one π C-C bonds (D) one sigma C-C and two π C-C bonds

Tardigrade Admin · Accepted Answer

In alkynes C ≡ C is present, in such bond one sigma and two π-bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas π-bonds are formed by unhybridised orbitals. Hence, it shows cylindrical shape.

Q. The cylindrical shape of an alkyne is due to

three sigma $C - C$ bonds

three $π C - C$ bonds

two sigma $C - C$ and one $π C - C$ bonds

one sigma $C - C$ and two $π C - C$ bonds

In alkynes $C \equiv C$ is present, in such bond one sigma and two $π$ -bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas $π$ -bonds are formed by unhybridised orbitals. Hence, it shows cylindrical shape.

Q. The cylindrical shape of an alkyne is due to

three sigma C−C bonds

three πC−C bonds

two sigma C−C and one πC−Cbonds

one sigma C−C and two πC−C bonds

In alkynes C≡C is present, in such bond one sigma and two π-bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas π-bonds are formed by unhybridised orbitals. Hence, it shows cylindrical shape.

three sigma $C - C$ bonds

three $π C - C$ bonds

two sigma $C - C$ and one $π C - C$ bonds

one sigma $C - C$ and two $π C - C$ bonds

In alkynes $C \equiv C$ is present, in such bond one sigma and two $π$ -bonds are present. Sigma bond is formed by sp-hybrid orbitals whereas $π$ -bonds are formed by unhybridised orbitals. Hence, it shows cylindrical shape.