The current through the battery shown in the circuit is

Question

The current through the battery shown in the circuit is Question

(A) 1.33A (B) 1.71A (C) 2.00 A (D) 2.31A

Tardigrade Admin · Accepted Answer

Since diode textitD1 is reverse biased, therefore it will act like an open circuit. Effective resistance of the circuit is textitR = 4 + 2 = 6 Ω . Current in the circuit is textitI = textitE / textitR = text12 / 6 = 2 A.

Q. The current through the battery shown in the circuit is

$1.33 A$

$1.71 A$

$2.00 A$

$2.31 A$

Since diode $D_{1}$ is reverse biased, therefore it will act like an open circuit.
Effective resistance of the circuit is $R = 4 + 2 = 6Ω$ .
Current in the circuit is $I = E / R = 12 /6 =$ 2 A.

Q. The current through the battery shown in the circuit is

1.33A

1.71A

2.00A

2.31A