The current through choke coil increases from zero to 6 A in 0.3 seconds and an induced e.m.f. of 30 V is produced. The inductance of the coil of choke is

Question

The current through choke coil increases from zero to 6 A in 0.3 seconds and an induced e.m.f. of 30 V is produced. The inductance of the coil of choke is (A) 5 H (B) 2.5 H (C) 1.5 H (D) 2 H

Tardigrade Admin · Accepted Answer

|e|=L (d i/d t) ⇒ 30=L × ((6-0)/0.3) ⇒ L=1.5 H

Q. The current through choke coil increases from zero to $6 A$ in $0.3$ seconds and an induced e.m.f. of $30 V$ is produced. The inductance of the coil of choke is

5 H

2.5 H

1.5 H

2 H

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow 30 = L \times \frac{( 6 - 0 )}{0.3}$
$\Rightarrow L = 1.5 H$

Q. The current through choke coil increases from zero to 6A in 0.3 seconds and an induced e.m.f. of 30V is produced. The inductance of the coil of choke is

5 H

2.5 H

1.5 H

2 H

∣e∣=Ldtdi​⇒30=L×0.3(6−0)​ ⇒L=1.5H

Q. The current through choke coil increases from zero to $6 A$ in $0.3$ seconds and an induced e.m.f. of $30 V$ is produced. The inductance of the coil of choke is

$∣ e ∣ = L \frac{d i}{d t} \Rightarrow 30 = L \times \frac{( 6 - 0 )}{0.3}$
$\Rightarrow L = 1.5 H$