Question

The current in the given circuit is:

• A. 0.4 A
• B. 0.3 A
• C. 0.2 A
• D. 0.1 A

Answer 1

Answer: (D)

From the figure, it is seen that the emf's of the cells are in opposite directions, hence net emf of the cell is $(5-2)=3V$, external resistance in the circuit is
$=10+20=30\Omega$
Hence, current in the circuit is given
$i=\frac{V}{R}$
$=\frac{3}{30}=0.1A$