The current in an LCR circuit is given by I=20 sin (100 π t+π /3) A. The voltage across the inductance L of 0.1 H at t =0 will be (in volt)

Question

The current in an LCR circuit is given by I=20 sin (100 π t+π /3) A. The voltage across the inductance L of 0.1 H at t =0 will be (in volt) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Given: I =20 sin (100 π t +π / 3) V L =ω L I 0 sin (π / 3+π / 2) at t =0 =ω L I 0 cos π / 3. =100 π × 0.1 × 20 × (1/2) =314 volt

Q. The current in an $L CR$ circuit is given by $I = 20 sin (100 π t + π$ /3) A. The voltage across the inductance $L$ of $0.1 H$ at $t = 0$ will be (in volt)

Given :
$I = 20 sin (100 π t + π /3)$
$V_{L} = ω L I_{0} sin (π /3 + π /2)$ at $t = 0$
$= ω L I_{0} cos π /3$ .
$= 100 π \times 0.1 \times 20 \times \frac{1}{2}$
$= 314$ volt

Q. The current in an LCR circuit is given by I=20sin(100πt+π /3) A. The voltage across the inductance L of 0.1H at t=0 will be (in volt)

Given : I=20sin(100πt+π/3) VL​=ωLI0​sin(π/3+π/2) at t=0 =ωLI0​cosπ/3. =100π×0.1×20×21​ =314 volt

Q. The current in an $L CR$ circuit is given by $I = 20 sin (100 π t + π$ /3) A. The voltage across the inductance $L$ of $0.1 H$ at $t = 0$ will be (in volt)

Given :
$I = 20 sin (100 π t + π /3)$
$V_{L} = ω L I_{0} sin (π /3 + π /2)$ at $t = 0$
$= ω L I_{0} cos π /3$ .
$= 100 π \times 0.1 \times 20 \times \frac{1}{2}$
$= 314$ volt