The current i and voltage V graphs for a given metallic wire at two different temperatures T1 and T2 are shown in the figure. It is concluded that

Question

The current i and voltage V graphs for a given metallic wire at two different temperatures T1 and T2 are shown in the figure. It is concluded that (A) T1 > T2 (B) T2 < T2 (C) T1 = T2 (D) T1 = 2T2

Tardigrade Admin · Accepted Answer

Slope of graph will give us reciprocal of resistance.

(a s \frac{1}{V} = \frac{1}{R})

Here resistance at temperature

T_{1}

is greater than that at

T_{2}

Since resistance of metallic wire is max at higher temperature then at lower temperature, hence

T_{1} > T_{2}

Q. The current i and voltage $V$ graphs for a given metallic wire at two different temperatures $T_{1}$ and $T_{2}$ are shown in the figure. It is concluded that

$T_{1} > T_{2}$

$T_{2} < T_{2}$

$T_{1} = T_{2}$

$T_{1} = 2 T_{2}$

Slope of graph will give us reciprocal of resistance.
$(a s \frac{1}{V} = \frac{1}{R})$
Here resistance at temperature $T_{1}$ is greater than that at $T_{2}$
Since resistance of metallic wire is max at higher temperature then at lower temperature, hence $T_{1} > T_{2}$

Q. The current i and voltage V graphs for a given metallic wire at two different temperatures T1​ and T2​ are shown in the figure. It is concluded that

T1​>T2​

T2​<T2​

T1​=T2​

T1​=2T2​