The current gain of a transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in base current by 5.0 μ A, will be

Question

The current gain of a transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in base current by 5.0 μ A, will be (A) 45 μ A, 250 μ A  (B) 240 μ A, 235 μ A  (C) 260 μ A, 255 μ A  (D) None of the above

Tardigrade Admin · Accepted Answer

Current gain, β=(Δ IC/Δ IB) where Δ IC is change in collector current and Δ IB is change in base current. ∴ Δ IC=β Δ IB=49 × 5=245 μ A Also, Δ IE=Δ IB+Δ IC =(245+5) μ A=250 μ A

Q. The current gain of a transistor in common emitter mode is $49$ . The change in collector current and emitter current corresponding to the change in base current by $5.0 μ A,$ will be

$45 μ A, 250 μ A$

$240 μ A, 235 μ A$

$260 μ A, 255 μ A$

None of the above

Current gain, $β = \frac{Δ I _{C}}{Δ I _{B}}$
where $Δ I_{C}$ is change in collector current
and $Δ I_{B}$ is change in base current.
$∴ Δ I_{C} = β Δ I_{B} = 49 \times 5 = 245 μ A$
Also, $Δ I_{E} = Δ I_{B} + Δ I_{C}$
$= (245 + 5) μ A = 250 μ A$

Q. The current gain of a transistor in common emitter mode is 49. The change in collector current and emitter current corresponding to the change in base current by 5.0μA, will be

45μA,250μA

240μA,235μA

260μA,255μA