The current flowing through an ac circuit is given by I=5 sin (120 π t) A How long will the current take to reach the peak value starting from zero?

Question

The current flowing through an ac circuit is given by I=5 sin (120 π t) A How long will the current take to reach the peak value starting from zero? (A) (1/60) s (B) 60 s (C) (1/120) s (D) (1/240) s

Tardigrade Admin · Accepted Answer

ω=120 π=(2 π/T) ⇒ T=(1/60) sec time taken to reach peak value =(T/4)=(1/240) S

Q. The current flowing through an ac circuit is given by
$I = 5 sin (120 π t) A$
How long will the current take to reach the peak value starting from zero?

$\frac{1}{60} s$

$60 s$

$\frac{1}{120} s$

$\frac{1}{240} s$

$ω = 120 π = \frac{2 π}{T} \Rightarrow T = \frac{1}{60} sec$
time taken to reach peak value $= \frac{T}{4} = \frac{1}{240} S$

Q. The current flowing through an ac circuit is given by I=5sin(120πt)A How long will the current take to reach the peak value starting from zero?

601​s

60s

1201​s

2401​s