The critical temperature and critical density of CO 2 are 27° C and 0.45 g cm -3 respectively. The van der Waal's constant ' a ' is :-

Question

The critical temperature and critical density of CO 2 are 27° C and 0.45 g cm -3 respectively. The van der Waal's constant ' a ' is :- (A) 0.22 L 2 atm mol -2 (B) 1.23 L 2 atm mol -2 (C) 2.71 L 2 atm mol -2 (D) 3.15 L 2 atm mol -2

Tardigrade Admin · Accepted Answer

dC-(M M/Vc) ⇒ 0.45 g / cm 3=(44 g / mol /3 b ) ⇒ b =(44 g / mol /0.45 × 1000 g / L × 3) ⇒ b =(44 L / mol /450 × 3) ∴ from T C =(8 a /27 Rb ) a= (TC × 27 R b/8) = ( 300 K × 27 × 0.0821 L atm k -1 mol -1 × (44/450 × 3) L mol -1/8) 2.71 L 2 atm mol -2

Q. The critical temperature and critical density of $C O_{2}$ are $2 7^{\circ} C$ and $0.45 g c m^{- 3}$ respectively. The van der Waal's constant ' $a$ ' is :-

$0.22 L^{2} a t mm o l^{- 2}$

$1.23 L^{2} a t mm o l^{- 2}$

$2.71 L^{2} a t mm o l^{- 2}$

$3.15 L^{2} a t mm o l^{- 2}$

Q. The critical temperature and critical density of CO2​ are 27∘C and 0.45gcm−3 respectively. The van der Waal's constant ' a ' is :-

0.22L2atmmol−2

1.23L2atmmol−2

2.71L2atmmol−2

3.15L2atmmol−2

dC​−Vc​MM​ ⇒0.45g/cm3=3b44g/mol​ ⇒b=0.45×1000g/L×344g/mol​ ⇒b=450×344L/mol​ ∴ from TC​=27Rb8a​ a=8TC​×27Rb​ =8300K×27×0.0821Latmk−1mol−1×450×344​Lmol−1​ 2.71L2atmmol−2

Q. The critical temperature and critical density of $C O_{2}$ are $2 7^{\circ} C$ and $0.45 g c m^{- 3}$ respectively. The van der Waal's constant ' $a$ ' is :-

$0.22 L^{2} a t mm o l^{- 2}$

$1.23 L^{2} a t mm o l^{- 2}$

$2.71 L^{2} a t mm o l^{- 2}$

$3.15 L^{2} a t mm o l^{- 2}$