The critical angle for glass-water boundary is C. If μ g=1.5 1.5 and μ ω =(4/3) then the value of C is:

Question

The critical angle for glass-water boundary is C. If μ g=1.5 1.5 and μ ω =(4/3) then the value of C is: (A)  sin -1( (3/2) )  (B)  sin -1( (4/3) )  (C)  sin -1( (8/9) )  (D)  sin -1( (1/2) )

Tardigrade Admin · Accepted Answer

From the relation sin C=(μ w/μ g)=(4/3/3/2)=(8/9) C= sin -1(8/9)

Q. The critical angle for glass-water boundary is C. If $μ_{g} = 1.5$ 1.5 and $μ_{ω} = \frac{4}{3}$ then the value of C is:

$sin^{- 1} (\frac{3}{2})$

$sin^{- 1} (\frac{4}{3})$

$sin^{- 1} (\frac{8}{9})$

$sin^{- 1} (\frac{1}{2})$

From the relation $sin C = \frac{μ _{w}}{μ _{g}} = \frac{4/3}{3/2} = \frac{8}{9}$ $C = sin^{- 1} \frac{8}{9}$

Q. The critical angle for glass-water boundary is C. If μg​=1.5 1.5 and μω​=34​ then the value of C is:

sin−1(23​)

sin−1(34​)

sin−1(98​)

sin−1(21​)