The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

Question

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is (A) Δ H > 0 and ΔS < 0 (B) Δ H < 0 and ΔS > 0 (C) Δ H < 0 and ΔS < 0 (D) Δ H < 0 and ΔS = 0

Tardigrade Admin · Accepted Answer

Δ G = Δ H - T Δ S For spontaneous process Δ S = +ve Δ H = - ve

Q. The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

$Δ$ H > 0 and $Δ$ S < 0

$Δ$ H < 0 and $Δ$ S > 0

$Δ$ H < 0 and $Δ$ S < 0

$Δ$ H < 0 and $Δ$ S = 0

$Δ G = Δ H - T Δ S$
For spontaneous process
$Δ S = + v e$
$Δ H = - v e$

Q. The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

ΔH > 0 and ΔS < 0

ΔH < 0 and ΔS > 0

ΔH < 0 and ΔS < 0

ΔH < 0 and ΔS = 0

ΔG=ΔH−TΔS For spontaneous process ΔS=+ve ΔH=−ve

$Δ$ H > 0 and $Δ$ S < 0

$Δ$ H < 0 and $Δ$ S > 0

$Δ$ H < 0 and $Δ$ S < 0

$Δ$ H < 0 and $Δ$ S = 0

$Δ G = Δ H - T Δ S$
For spontaneous process
$Δ S = + v e$
$Δ H = - v e$