Tardigrade
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Tardigrade
Question
Chemistry
The correct structure of Fe(CO)5 is (at. no. of Fe = 26)
Q. The correct structure of
F
e
(
CO
)
5
is (at. no. of
F
e
=
26
)
2535
275
JIPMER
JIPMER 2010
Coordination Compounds
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A
trigonal bipyramidal
59%
B
octahedral
11%
C
tetrahedral
19%
D
square pyramidal
11%
Solution:
26
F
e
:
[
A
r
]
3
d
6
4
s
2
