The correct set of four quantum numbers for the valence electrons of rubidium atom (Z = 37) is

Question

The correct set of four quantum numbers for the valence electrons of rubidium atom (Z = 37) is (A) 5,0,0,+(1/2) (B) 5,1,0,+(1/2) (C) 5,1,1,+(1/2) (D) 5,0,1,+(1/2)

Tardigrade Admin · Accepted Answer

E.C of Rubidium is ( Z =37)=1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 4 s 2 3 d 10 4 p 6 5 s 1 The valence electron is in 5 s orbital. Its 4 quantum numbers are- n =5, l =0, m =0, s =+(1/2)

Q. The correct set of four quantum numbers for the valence electrons of rubidium atom $(Z = 37)$ is

$5, 0, 0, + \frac{1}{2}$

$5, 1, 0, + \frac{1}{2}$

$5, 1, 1, + \frac{1}{2}$

$5, 0, 1, + \frac{1}{2}$

E.C of Rubidium is $(Z = 37) = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{1}$
The valence electron is in $5 s$ orbital.
Its 4 quantum numbers are- $n = 5, l = 0, m = 0, s = + \frac{1}{2}$

Q. The correct set of four quantum numbers for the valence electrons of rubidium atom (Z=37) is

5,0,0,+21​

5,1,0,+21​

5,1,1,+21​

5,0,1,+21​