The correct sequence of dipole moments among the chlorides of methane is

Question

The correct sequence of dipole moments among the chlorides of methane is (A) CHCl3 < CH2Cl2 > CH3 Cl > CCl4 (B) CH2Cl2 > CH3Cl > CHCl3 > CCl4 (C) CH3Cl > CH2Cl2 > CHCl3 > CCl4 (D) CH2Cl2 > CHCl3 > CH3Cl > CCl4

Tardigrade Admin · Accepted Answer

μCCl4 = 0

The resultant dipole moment of three C -H bonds = 0.4 D. Net dipole moment = 1.9 D

The resultant of two C -H bonds =√(0.4)2+(0.4)2+2 ×(0.4)2 × cos 109.5° =√0.16 + 0.16 -0.2873 = 0.18 D The resultant of two C - Cl bonds =√(1.5)2+(1.5)2+2×(1.5)2 cos 109.5° =√2.25+2.25 + 2×2.25 × cos 109.5° =√4.5 - 4.04 =√0.46 = 0.678 ∴ μcal = 0.858 D but experimentally for CH2Cl2, μ = 1.59 D. The resultant of three C - Cl bonds = 1.5 D Experimental dipole moment of CHCl3 = 1.15 D

Q. The correct sequence of dipole moments among the chlorides of methane is

$C H C l_{3} < C H_{2} C l_{2} > C H_{3} Cl > CC l_{4}$

$C H_{2} C l_{2} > C H_{3} Cl > C H C l_{3} > CC l_{4}$

$C H_{3} Cl > C H_{2} C l_{2} > C H C l_{3} > CC l_{4}$

$C H_{2} C l_{2} > C H C l_{3} > C H_{3} Cl > CC l_{4}$

Q. The correct sequence of dipole moments among the chlorides of methane is

CHCl3​<CH2​Cl2​>CH3​Cl>CCl4​

CH2​Cl2​>CH3​Cl>CHCl3​>CCl4​

CH3​Cl>CH2​Cl2​>CHCl3​>CCl4​

CH2​Cl2​>CHCl3​>CH3​Cl>CCl4​

$C H C l_{3} < C H_{2} C l_{2} > C H_{3} Cl > CC l_{4}$

$C H_{2} C l_{2} > C H_{3} Cl > C H C l_{3} > CC l_{4}$

$C H_{3} Cl > C H_{2} C l_{2} > C H C l_{3} > CC l_{4}$

$C H_{2} C l_{2} > C H C l_{3} > C H_{3} Cl > CC l_{4}$