The correct sequence of decreasing number of π -bonds in the structure of H2SO3, H2SO4 and H2S2O7 is:

Question

The correct sequence of decreasing number of π -bonds in the structure of H2SO3, H2SO4 and H2S2O7 is: (A)  textH2 textS2 textO7> textH2 textS textO3> textH2 textS textO4 (B)  textH2 textS2 textO7> textH2 textS textO4> textH2 textS textO3 (C)  textH2 textS textO4> textH2 textS2 textO7> textH2 textS textO3 (D)  textH2 textS textO3> textH2 textS textO4> textH2 textS2 textO7

Tardigrade Admin · Accepted Answer

Q. The correct sequence of decreasing number of $π$ -bonds in the structure of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is:

$H_{2} S_{2} O_{7} > H_{2} S O_{3} > H_{2} S O_{4}$

$H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$

$H_{2} S O_{4} > H_{2} S_{2} O_{7} > H_{2} S O_{3}$

$H_{2} S O_{3} > H_{2} S O_{4} > H_{2} S_{2} O_{7}$

Q. The correct sequence of decreasing number of π -bonds in the structure of H2​SO3​,H2​SO4​ and H2​S2​O7​ is:

H2​S2​O7​>H2​SO3​>H2​SO4​

H2​S2​O7​>H2​SO4​>H2​SO3​

H2​SO4​>H2​S2​O7​>H2​SO3​

H2​SO3​>H2​SO4​>H2​S2​O7​

Q. The correct sequence of decreasing number of $π$ -bonds in the structure of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is:

$H_{2} S_{2} O_{7} > H_{2} S O_{3} > H_{2} S O_{4}$

$H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$

$H_{2} S O_{4} > H_{2} S_{2} O_{7} > H_{2} S O_{3}$

$H_{2} S O_{3} > H_{2} S O_{4} > H_{2} S_{2} O_{7}$