The correct sequence of decreasing number of π-bonds in the structures of H2SO3, H2SO4 and H2S2O7 is :

Question

The correct sequence of decreasing number of π-bonds in the structures of H2SO3, H2SO4 and H2S2O7 is : (A) H2SO3 > H2SO4 > H2S2O7 (B) H2SO4 > H2S2O7 > H2SO3 (C) H2S2O7 > H2SO4> H2SO3 (D) H2S2O7 > H2SO3 > H2SO4

Tardigrade Admin · Accepted Answer

Correct answer is (c) H2S2O7 > H2SO4> H2SO3

Q. The correct sequence of decreasing number of $π$ -bonds in the structures of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is :

$H_{2} S O_{3} > H_{2} S O_{4} > H_{2} S_{2} O_{7}$

$H_{2} S O_{4} > H_{2} S_{2} O_{7} > H_{2} S O_{3}$

$H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$

$H_{2} S_{2} O_{7} > H_{2} S O_{3} > H_{2} S O_{4}$

Correct answer is (c) $H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$

Q. The correct sequence of decreasing number of π-bonds in the structures of H2​SO3​,H2​SO4​ and H2​S2​O7​ is :

H2​SO3​>H2​SO4​>H2​S2​O7​

H2​SO4​>H2​S2​O7​>H2​SO3​

H2​S2​O7​>H2​SO4​>H2​SO3​

H2​S2​O7​>H2​SO3​>H2​SO4​