Question

The correct order regarding the electronegativity of hybrid orbitals of carbon is

• A. $sp>s{p}^2<s{p}^3$
• B. $sp>s{p}^2>s{p}^3$
• C. $sp<s{p}^2>s{p}^3$
• D. $sp<s{p}^2<s{p}^3$

Answer 1

Answer: (B)

The correct order regarding the electronegativity of hybrid orbitals of carbon is sp $>s{p}^2>s{p}^3$ because in sp, sp${}^{2}ands{p}^3$ hybrid orbitals s-orbital character is $50\%,33.3\%$ and $25\%$ respectively and due to higher s-character electron attracting tendency, i.e. electronegativity increases.