Question

The correct order of the size of iodine species, I, $I^{-}$ and $I^{+}$ is

• A. $I>I^{-}>I^{+}$
• B. $I^{-}>I>I^{+}$
• C. $I^{+}>I>I^{-}$
• D. $I^{-}>I^{+}>I$

Answer 1

Answer: (B)

$I^{-}>I>I^{+}$. As the number of electron decreases (but proton number remains same) so effective nuclear charge increases and so size decrease