The correct order of the ligands, OH -, NO 3-, PPh 3, pyridine, according to their increasing field strength is

Question

The correct order of the ligands, OH -, NO 3-, PPh 3, pyridine, according to their increasing field strength is (A) NO 3-< OH -< pyridine < PPh 3 (B) OH -< NO 3-< PPh 3< pyridine (C) OH -< NO 3-< pyridine < PPh 3 (D) NO 3-< OH -< PPh 3< Pyridine

Tardigrade Admin · Accepted Answer

Increasing order of crystal field splitting power is as follows: underset textweak field ligandNO-3 < OH- < underset textstrong field ligand textpyridine < PPh3

Q. The correct order of the ligands, $O H^{-}, N O_{3}^{-}, PP h_{3}$ , pyridine, according to their increasing field strength is

$N O_{3}^{-} < O H^{-} <$ pyridine $< PP h_{3}$

$O H^{-} < N O_{3}^{-} < PP h_{3} <$ pyridine

$O H^{-} < N O_{3}^{-} <$ pyridine $< PP h_{3}$

$N O_{3}^{-} < O H^{-} < PP h_{3} <$ Pyridine

Increasing order of crystal field splitting power is as follows:
$weak field ligand N O_{3}^{-} < O H^{-} < strong field ligand pyridine < PP h_{3}$

Q. The correct order of the ligands, OH−,NO3−​,PPh3​, pyridine, according to their increasing field strength is

NO3−​<OH−< pyridine <PPh3​

OH−<NO3−​<PPh3​< pyridine

OH−<NO3−​< pyridine <PPh3​

NO3−​<OH−<PPh3​< Pyridine