Question

The correct order of shielding effect of $s,p,d$ and $f$ orbitals is

• A. $s>p>d>f$
• B. $s<p<d>f$
• C. $s<p<d<f$
• D. $s>p<d<f$

Answer 1

Answer: (A)

$s$ is more closer to nucleus i.e., shielding effect $\alpha$ distance from nucleus.
$\therefore s>p>d>f$