The correct order of SN2 / E2 ratio for the % yield of product of the following halide is :

Question

The correct order of SN2 / E2 ratio for the % yield of product of the following halide is : (A) R >S >Q >P (B) R >Q >S >P (C) P >R >S >Q (D) Q >P >R >S

Tardigrade Admin · Accepted Answer

Rate of S N 2 reaction: 1°>2°>3°, as β -branching increases steric crowding increases in transition state so it makes less stable T.S.

Q. The correct order of $S_{N} 2/ E_{2}$ ratio for the $%$ yield of product of the following halide is :

$R > S > Q > P$

$R > Q > S > P$

$P > R > S > Q$

$Q > P > R > S$

Rate of $S_{N} 2$ reaction $: 1^{\circ} > 2^{\circ} > 3^{\circ},$ as $β$ -branching increases steric crowding increases in transition state so it makes less stable T.S.

Q. The correct order of SN​2/E2​ ratio for the % yield of product of the following halide is :

R>S>Q>P

R>Q>S>P

P>R>S>Q

Q>P>R>S