The correct order of relative acidity is

Question

The correct order of relative acidity is (A)  HClO>HClO2>HClO3>HClO4  (B)  HClO4>HClO3>HClO2>HClO  (C)  HClO>HClO4>HClO2>HClO3  (D)  HClO3>HClO2>HClO4>HClO

Tardigrade Admin · Accepted Answer

Key Idea: Strength of oxyacids increases with oxidation state of central atom. Find the oxidation state of chlorine in all the oxyacids to decide the decreasing acidic strength among oxyacids. (i) HClO4+1+x+(-2× 4)=0∴ x=+7 (ii) HClO3+1+x+(-2× 3)=0∴ x=+5 (iii) HClO2+1+x(-2× 2)=0∴ x=+3 (iv) HClO+1+x+(-2× 1)=0∴ x=+1 ∴ textHCl textO text4 is strongest acid and textHClO is weakest acid. ∴ Correct order of acidic strength is HClO4>HClO3>HClO2>HClO

Q. The correct order of relative acidity is

$H ClO > H Cl O_{2} > H Cl O_{3} > H Cl O_{4}$

$H Cl O_{4} > H Cl O_{3} > H Cl O_{2} > H ClO$

$H ClO > H Cl O_{4} > H Cl O_{2} > H Cl O_{3}$

$H Cl O_{3} > H Cl O_{2} > H Cl O_{4} > H ClO$

Q. The correct order of relative acidity is

HClO>HClO2​>HClO3​>HClO4​

HClO4​>HClO3​>HClO2​>HClO

HClO>HClO4​>HClO2​>HClO3​

HClO3​>HClO2​>HClO4​>HClO

$H ClO > H Cl O_{2} > H Cl O_{3} > H Cl O_{4}$

$H Cl O_{4} > H Cl O_{3} > H Cl O_{2} > H ClO$

$H ClO > H Cl O_{4} > H Cl O_{2} > H Cl O_{3}$

$H Cl O_{3} > H Cl O_{2} > H Cl O_{4} > H ClO$