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Q.
The correct order of relative acidity is
VMMC MedicalVMMC Medical 2007
Solution:
Key Idea: Strength of oxyacids increases with oxidation state of central atom. Find the oxidation state of chlorine in all the oxyacids to decide the decreasing acidic strength among oxyacids. (i) $ HCl{{O}_{4}}+1+x+(-2\times 4)=0\therefore x=+7 $ (ii) $ HCl{{O}_{3}}+1+x+(-2\times 3)=0\therefore x=+5 $ (iii) $ HCl{{O}_{2}}+1+x(-2\times 2)=0\therefore x=+3 $ (iv) $ HClO+1+x+(-2\times 1)=0\therefore x=+1 $ $ \therefore $ $ \text{HCl}{{\text{O}}_{\text{4}}} $ is strongest acid and $ \text{HClO} $ is weakest acid. $ \therefore $ Correct order of acidic strength is $ HCl{{O}_{4}}>HCl{{O}_{3}}>HCl{{O}_{2}}>HClO $