The correct order of pH of solutions of textCuS textO text4 text,NaCN,NaCl and water is

Question

The correct order of pH of solutions of textCuS textO text4 text,NaCN,NaCl and water is (A) CuSO4NaCN=H2 textO>NaCl (C) CuSO4=H2O>NaCN>NaCl (D) CuSO4

Tardigrade Admin · Accepted Answer

textCuS textO text4 is a salt of weak base [CO(OH)2] and strong acid (H2SO4), hence it will be acidic in nature. Therefore, pH of its solution must be less than 7. textNaCl is a salt of strong base text(NaOH) and strong acid text(HCl), hence it will be neutral in nature. Therefore pH of its solution will be 7. Similarly, textH text2 textO is neutral itself in nature, therefore its pH also will be 7. On the other hand, textNaCN is a salt of strong base ( textNaOH) and weak acid text(HCN), so its solution must be basic in nature showing pH greater than 7. Hence, correct order of pH is as follows: CuSO4<NaCl=H2O<NaCN.

Q. The correct order of pH of solutions of $CuS O_{4},NaCN,NaCl$ and water is

$C u S O_{4} < N a CN < N a C I = H_{2} O$

$C u S O_{4} > N a CN = H_{2} O > N a Cl$

$C u S O_{4} = H_{2} O > N a CN > N a Cl$

$C u S O_{4} < N a Cl = H_{2} O < N a CN$

Q. The correct order of pH of solutions of CuSO4​,NaCN,NaCl and water is

CuSO4​<NaCN<NaCI=H2​O

CuSO4​>NaCN=H2​O>NaCl

CuSO4​=H2​O>NaCN>NaCl

CuSO4​<NaCl=H2​O<NaCN

Q. The correct order of pH of solutions of $CuS O_{4},NaCN,NaCl$ and water is

$C u S O_{4} < N a CN < N a C I = H_{2} O$

$C u S O_{4} > N a CN = H_{2} O > N a Cl$

$C u S O_{4} = H_{2} O > N a CN > N a Cl$

$C u S O_{4} < N a Cl = H_{2} O < N a CN$