The correct order of normal boiling points of O2, N2, NH3 and CH4 for whom the values of van der Waals constant 'a' are 1.360, 1.390, 4.170 and 2.253 L2 atm mol-2 respectively, is:

Question

The correct order of normal boiling points of O2, N2, NH3 and CH4 for whom the values of van der Waals constant 'a' are 1.360, 1.390, 4.170 and 2.253 L2 atm mol-2 respectively, is: (A) O2 < N2 < NH3 < CH4 (B) O2 < N2 < CH4 < NH3 (C) NH3 < CH 4 < N2 < O2 (D) NH3 < CH4 < O2 < N2

Tardigrade Admin · Accepted Answer

van der Waal's constant 'a' depicts the correction of intermolecular forces. Higher the value of ' a ' stronger the intermolecular force. The order of normal boiling points: O 2< N 2< CH 4< NH 3.

Q. The correct order of normal boiling points of $O_{2}, N_{2}, N H_{3}$ and $C H_{4}$ for whom the values of van der Waals constant ' $a$ ' are $1.360, 1.390, 4.170$ and $2.253 L^{2}$ atm $m o l^{- 2}$ respectively, is:

$O_{2} < N_{2} < N H_{3} < C H_{4}$

$O_{2} < N_{2} < C H_{4} < N H_{3}$

$N H_{3} < C H_{4} < N_{2} < O_{2}$

$N H_{3} < C H_{4} < O_{2} < N_{2}$

van der Waal's constant 'a' depicts the correction of intermolecular forces. Higher the value of ' $a$ ' stronger the intermolecular force. The order of normal boiling points : $O_{2} < N_{2} < C H_{4} < N H_{3}$ .

Q. The correct order of normal boiling points of O2​,N2​,NH3​ and CH4​ for whom the values of van der Waals constant 'a' are 1.360,1.390,4.170 and 2.253L2 atm mol−2 respectively, is:

O2​<N2​<NH3​<CH4​

O2​<N2​<CH4​<NH3​

NH3​<CH4​<N2​<O2​

NH3​<CH4​<O2​<N2​