Question

The correct order of magnetic moments (spin only values in BM) among the following is (Atomic numbers: $Mn=25,Fe=26,Co=27$ )

• A. ${\left[MnC{l}_4\right]}^{2-}>{\left[CoC{l}_4\right]}^{2-}>{\left[Fe(CN{)}_6\right]}^{4-}$
• B. ${\left[MnC{l}_4\right]}^{2-}>{\left[Fe(CN{)}_6\right]}^{4-}>{\left[CoC{l}_4\right]}^{2-}$
• C. ${\left[Fe(CN{)}_6\right]}^{4-}>{\left[MnC{l}_4\right]}^{2-}>{\left[CoC{l}_4\right]}^{2-}$
• D. ${\left[Fe(CN{)}_6\right]}^{4-}>{\left[CoC{l}_4\right]}^{2-}>{\left[MnC{l}_4\right]}^{2-}$

Answer 1

Answer: (A)

As the number of unpaired electrons in the central atom increases, magnetic moment of the complex increases.


$\therefore$ The order of magnetic moments is
$[MnC{l}_4{]}^{2-}>[CoC{l}_4{]}^{2-}>[Fe(CN{)}_6{]}^{4-}$