The correct order of leaving group ability in a nucleophilic substitution reaction is

Question

B r^{-} > C l^{-} > C H_{3} CO O^{-} > H O^{-} H^{-}

Because the best leaving group is that which is conjugal base of strong acid.

Tardigrade Admin · Accepted Answer

The correct order of leaving group ability in a nucleophilic substitution reaction is Br -> Cl -> CH 3 COO -> HO - H - Because the best leaving group is that which is conjugal base of strong acid.

Q. The correct order of leaving group ability in a nucleophilic substitution reaction is

$B r^{-} > C l^{-} > C H_{3} C O_{2}^{-} > H O^{-} > H^{-}$

$H^{-} > O H^{-} > C H_{3} C O_{2}^{-} > C l^{-} > B r^{-}$

$B r^{-} C H_{3} C O_{2}^{-} C l^{-} > O H^{-} > H^{-}$

$C H_{3} C O_{2}^{-} > B r^{-} > C l^{-} > O H^{-} > H^{-}$

The correct order of leaving group ability in a nucleophilic substitution reaction is
$B r^{-} > C l^{-} > C H_{3} CO O^{-} > H O^{-} H^{-}$
Because the best leaving group is that which is conjugal base of strong acid.

Q. The correct order of leaving group ability in a nucleophilic substitution reaction is

Br−>Cl−>CH3​CO2−​>HO−>H−

H−>OH−>CH3​CO2−​>Cl−>Br−

Br−CH3​CO2−​Cl−>OH−>H−

CH3​CO2−​>Br−>Cl−>OH−>H−

The correct order of leaving group ability in a nucleophilic substitution reaction is Br−>Cl−>CH3​COO−>HO−H− Because the best leaving group is that which is conjugal base of strong acid.

$B r^{-} > C l^{-} > C H_{3} C O_{2}^{-} > H O^{-} > H^{-}$

$H^{-} > O H^{-} > C H_{3} C O_{2}^{-} > C l^{-} > B r^{-}$

$B r^{-} C H_{3} C O_{2}^{-} C l^{-} > O H^{-} > H^{-}$

$C H_{3} C O_{2}^{-} > B r^{-} > C l^{-} > O H^{-} > H^{-}$

The correct order of leaving group ability in a nucleophilic substitution reaction is
$B r^{-} > C l^{-} > C H_{3} CO O^{-} > H O^{-} H^{-}$
Because the best leaving group is that which is conjugal base of strong acid.