The correct order of increasing oxidising power in the series is

Question

The correct order of increasing oxidising power in the series is (A) VO+2< Cr2O2-7< MnO-4 (B) Cr2O2-7< VO+2< MnO-4 (C) Cr2O2-7< MnO-4< VO+2 (D) MnO-4 < Cr2O2-7< VO+2

Tardigrade Admin · Accepted Answer

Greater the oxidation state, stronger the oxidising power underset(V+5)VO+2< underset(Cr6+)Cr2O2-7< underset(Mn7+)MnO-4

Q. The correct order of increasing oxidising power in the series is

$V O_{2}^{+} < C r_{2} O_{7}^{2 -} < M n O_{4}^{-}$

$C r_{2} O_{7}^{2 -} < V O_{2}^{+} < M n O_{4}^{-}$

$C r_{2} O_{7}^{2 -} < M n O_{4}^{-} < V O_{2}^{+}$

$M n O_{4}^{-} < C r_{2} O_{7}^{2 -} < V O_{2}^{+}$

Greater the oxidation state, stronger the oxidising power $(V^{+ 5}) V O_{2}^{+} < (C r^{6 +}) C r_{2} O_{7}^{2 -} < (M n^{7 +}) M n O_{4}^{-}$

Q. The correct order of increasing oxidising power in the series is

VO2+​<Cr2​O72−​<MnO4−​

Cr2​O72−​<VO2+​<MnO4−​

Cr2​O72−​<MnO4−​<VO2+​

MnO4−​<Cr2​O72−​<VO2+​

Greater the oxidation state, stronger the oxidising power (V+5)VO2+​​<(Cr6+)Cr2​O72−​​<(Mn7+)MnO4−​​

$V O_{2}^{+} < C r_{2} O_{7}^{2 -} < M n O_{4}^{-}$

$C r_{2} O_{7}^{2 -} < V O_{2}^{+} < M n O_{4}^{-}$

$C r_{2} O_{7}^{2 -} < M n O_{4}^{-} < V O_{2}^{+}$

$M n O_{4}^{-} < C r_{2} O_{7}^{2 -} < V O_{2}^{+}$

Greater the oxidation state, stronger the oxidising power $(V^{+ 5}) V O_{2}^{+} < (C r^{6 +}) C r_{2} O_{7}^{2 -} < (M n^{7 +}) M n O_{4}^{-}$