The correct order of increasing C- O bond length of CO, CO32- , CO2 is

Question

The correct order of increasing C- O bond length of CO, CO32- , CO2 is (A)  CO32- < CO2 < CO  (B)  CO2 < CO32- < CO  (C)  CO < CO32- < CO2  (D)  CO < CO2 < CO32-

Tardigrade Admin · Accepted Answer

Method (1) Bond-multiplicity increases bond-length.
Thus,
(i)

C \equiv) \to

has least bond-length.
(ii)

O = C + O \to

next to

C = O

.
(iii)
Hence, increasing order of bond-length is

CO < C O_{2} < C O_{3}^{2 -}

Method (2)
(i) More be the value of bond-order smaller be the bond-length and more be the bond-energy.
(ii) Bond-order (BO) =
Total number of bonds associated between two atoms in all structure
T otal number of canonical forms
(a)

CO \to C \equiv O \to BO = \frac{3}{1} = 3

(b)

C O_{2} \to O = C = C \to BO = \frac{4}{2} = 2

Hence, order of bond-length

CO < C O_{2} < C O_{3}^{2 -}

Epimer is used to designate diastereomers that differ in configuration at only one chiral centre.

Q. The correct order of increasing C- O bond length of
$CO, C O_{3}^{2 -}, C O_{2}$ is

$C O_{3}^{2 -} < C O_{2} < CO$

$C O_{2} < C O_{3}^{2 -} < CO$

$CO < C O_{3}^{2 -} < C O_{2}$

$CO < C O_{2} < C O_{3}^{2 -}$

Q. The correct order of increasing C- O bond length of CO,CO32−​,CO2​ is

CO32−​<CO2​<CO

CO2​<CO32−​<CO

CO<CO32−​<CO2​

CO<CO2​<CO32−​

Q. The correct order of increasing C- O bond length of
$CO, C O_{3}^{2 -}, C O_{2}$ is

$C O_{3}^{2 -} < C O_{2} < CO$

$C O_{2} < C O_{3}^{2 -} < CO$

$CO < C O_{3}^{2 -} < C O_{2}$

$CO < C O_{2} < C O_{3}^{2 -}$