The correct order of increasing bond angles in the following species is

Question

The correct order of increasing bond angles in the following species is (A) Cl2O < ClO2 < ClO2-  (B) ClO2 < Cl2O < ClO2-  (C) Cl2O < ClO2- < ClO2 (D) ClO2- < Cl2O < ClO2

Tardigrade Admin · Accepted Answer

The correct order of increasing bond angles in the following species is Cl 2 O < ClO 2-< ClO 2 This is because, In ClO 2-there are two lone pairs of electrons which repel each other due to which two oxygen atom come closer leading to decrease in bond angle. Therefore the bond angle in ClO 2-is less than 118° which is bond angle in ClO 2 which has less number of electrons on chlorine.

Q. The correct order of increasing bond angles in the following species is

$C l_{2} O < Cl O_{2} < Cl O_{2}^{-}$

$Cl O_{2} < C l_{2} O < Cl O_{2}^{-}$

$C l_{2} O < Cl O_{2}^{-} < Cl O_{2}$

$Cl O_{2}^{-} < C l_{2} O < Cl O_{2}$

Q. The correct order of increasing bond angles in the following species is

Cl2​O<ClO2​<ClO2−​

ClO2​<Cl2​O<ClO2−​

Cl2​O<ClO2−​<ClO2​

ClO2−​<Cl2​O<ClO2​

$C l_{2} O < Cl O_{2} < Cl O_{2}^{-}$

$Cl O_{2} < C l_{2} O < Cl O_{2}^{-}$

$C l_{2} O < Cl O_{2}^{-} < Cl O_{2}$

$Cl O_{2}^{-} < C l_{2} O < Cl O_{2}$