The correct order of increasing basicity of the following is H 2 O , OH -, CH 3 OH , CH 3 O -

Question

The correct order of increasing basicity of the following is H 2 O , OH -, CH 3 OH , CH 3 O - (A) CH 3 OH < H 2 O < OH -< CH 3 O - (B) H 2 O < CH 3 OH < CH 3 O -< OH - (C) H 2 O < CH 3 OH < OH -< CH 3 O - (D) CH 3 OH < H 2 O < CH 3 O -< OH -

Tardigrade Admin · Accepted Answer

Basicity depends upon the availability of lone pair of electrons for donation. Between

H_{2} O

and

C H_{3} O H

, the later is more basic because of the presence of electron donating

- C H_{3}

group.
Thus,

C H_{3} O H > H_{2} O

(basicity order)
Conjugate base of weaker acid is strong.
Thus,

C H_{3} O^{-} > O H^{-}

(basicity order)
Hence, the increasing order of basicity is

C H_{3} O^{-} > O H^{-} > C H_{3} O H > H_{2} O

Q. The correct order of increasing basicity of the following is
$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

$C H_{3} O H < H_{2} O < O H^{-} < C H_{3} O^{-}$

$H_{2} O < C H_{3} O H < C H_{3} O^{-} < O H^{-}$

$H_{2} O < C H_{3} O H < O H^{-} < C H_{3} O^{-}$

$C H_{3} O H < H_{2} O < C H_{3} O^{-} < O H^{-}$

Q. The correct order of increasing basicity of the following is H2​O,OH−,CH3​OH,CH3​O−

CH3​OH<H2​O<OH−<CH3​O−

H2​O<CH3​OH<CH3​O−<OH−

H2​O<CH3​OH<OH−<CH3​O−

CH3​OH<H2​O<CH3​O−<OH−

Q. The correct order of increasing basicity of the following is
$H_{2} O, O H^{-}, C H_{3} O H, C H_{3} O^{-}$

$C H_{3} O H < H_{2} O < O H^{-} < C H_{3} O^{-}$

$H_{2} O < C H_{3} O H < C H_{3} O^{-} < O H^{-}$

$H_{2} O < C H_{3} O H < O H^{-} < C H_{3} O^{-}$

$C H_{3} O H < H_{2} O < C H_{3} O^{-} < O H^{-}$