Question

The correct order of hybridisation of the central atom in the following species $N{H}_3,{\left[PtC{l}_4\right]}^{2-},PC{l}_5{\left[BC{l}_4\right]}^{-}$

• A. $s{p}^3,ds{p}^2,ds{p}^3,s{p}^2$
• B. $s{p}^3,ds{p}^2,s{p}^3,s{p}^3$
• C. $s{p}^3,ds{p}^2,ds{p}^3,s{p}^3$
• D. $s{p}^3,s{p}^2,ds{p}^3,s{p}^3$

Answer 1

Answer: (C)

$\left[N{H}_3\right]\to$ Three bond pairs $+$ one lone pair $\to$ Tetrahedral $\to s{p}^3$ hybridisation.
${\left[PtC{l}_4\right]}^{2-}\to$ Four hybrid orbitals $\to$ square planar $\to ds{p}^2$ hybridisation.
$\left[PC{l}_5\right]\to$ Five hybrid orbitals $\to$ trigonal bipyramid $\to ds{p}^3$ hybridisation.
${\left[BC{l}_4\right]}^{-}\to$ Four hybrid orbitals $\to$ tetrahedral $\to s{p}^3$ hybridisation.