The correct order of decreasing ionic character of PbF2, PbCl2, PbBr2 and Pbl2 are

Question

The correct order of decreasing ionic character of PbF2, PbCl2, PbBr2 and Pbl2 are (A) PbF2 > PbCl2 > PbBr2 > PbI2 (B) PbF2 > PbBr2 > PbCl2 > PbI2 (C) PbF2 < PbCl2 < PbBr2 < PbI2 (D) PbF2 < PbBr2 < PbCl2 < PbI2

Tardigrade Admin · Accepted Answer

Correct answer is (a) PbF2 > PbCl2 > PbBr2 > PbI2

Q. The correct order of decreasing ionic character of $P b F_{2}, P b C l_{2}, P b B r_{2}$ and $P b l_{2}$ are

$P b F_{2} > P b C l_{2} > P b B r_{2} > P b I_{2}$

$P b F_{2} > P b B r_{2} > P b C l_{2} > P b I_{2}$

$P b F_{2} < P b C l_{2} < P b B r_{2} < P b I_{2}$

$P b F_{2} < P b B r_{2} < P b C l_{2} < P b I_{2}$

Correct answer is (a) $P b F_{2} > P b C l_{2} > P b B r_{2} > P b I_{2}$

Q. The correct order of decreasing ionic character of PbF2​,PbCl2​,PbBr2​ and Pbl2​ are

PbF2​>PbCl2​>PbBr2​>PbI2​

PbF2​>PbBr2​>PbCl2​>PbI2​

PbF2​<PbCl2​<PbBr2​<PbI2​

PbF2​<PbBr2​<PbCl2​<PbI2​