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Chemistry
The correct order of decreasing ionic character of PbF2, PbCl2, PbBr2 and Pbl2 are
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Q. The correct order of decreasing ionic character of $PbF_2, PbCl_2, PbBr_2$ and $Pbl_2$ are
A
$PbF_2 > PbCl_2 > PbBr_2 > PbI_2$
35%
B
$PbF_2 > PbBr_2 > PbCl_2 > PbI_2$
21%
C
$PbF_2 < PbCl_2 < PbBr_2 < PbI_2$
25%
D
$PbF_2 < PbBr_2 < PbCl_2 < PbI_2$
20%
Solution:
Correct answer is (a) $PbF_2 > PbCl_2 > PbBr_2 > PbI_2$