The correct order of bond angles (smallest first) in H2S, NH3, BF3 and SiH4 is

Question

The correct order of bond angles (smallest first) in H2S, NH3, BF3 and SiH4 is (A)  H2S < SiH4 < NH3< BF3  (B)  NH3< H2S< SiH4< BF3  (C)  H2S < NH3 < SiH4 < BF3  (D)  H2S< NH3< BF3< SiH4

Tardigrade Admin · Accepted Answer

Presence of lone pairs of electrons greatly affects the bond angle. As the number of lone pairs of electrons increases, bond angle decreases. Thus, the correct order of bond angles, <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/441fa8527bbe680a7b48fdb50f6a8898-.png" />

Q. The correct order of bond angles (smallest first) in $H_{2} S, N H_{3}, B F_{3}$ and $S i H_{4}$ is

$H_{2} S < S i H_{4} < N H_{3} < B F_{3}$

$N H_{3} < H_{2} S < S i H_{4} < B F_{3}$

$H_{2} S < N H_{3} < S i H_{4} < B F_{3}$

$H_{2} S < N H_{3} < B F_{3} < S i H_{4}$

Presence of lone pairs of electrons greatly affects the bond angle. As the number of lone pairs of electrons increases, bond angle decreases. Thus, the correct order of bond angles,

Q. The correct order of bond angles (smallest first) in H2​S,NH3​,BF3​ and SiH4​ is

H2​S<SiH4​<NH3​<BF3​

NH3​<H2​S<SiH4​<BF3​

H2​S<NH3​<SiH4​<BF3​