The correct option for free expansion of an ideal gas under adiabatic condition is :

Question

The correct option for free expansion of an ideal gas under adiabatic condition is : (A) q = 0, Δ T = 0 and w = 0 (B) q = 0, Δ T < 0 and w > 0 (C) q < 0, Δ T = 0 and w = 0 (D) q > 0, Δ T > 0 and w > 0

Tardigrade Admin · Accepted Answer

For free expansion of ideal gas P e x t = 0 W p v = 0 q = 0 (adiabatic process) Δ E = q + w Δ E = 0 Δ E = n C v m Δ T = 0 q = 0 , Δ mathbf T = 0 , w = 0

Q. The correct option for free expansion of an ideal gas under adiabatic condition is :

q = 0, $Δ$ T = 0 and w = 0

q = 0, $Δ$ T < 0 and w > 0

q < 0, $Δ$ T = 0 and w = 0

q > 0, $Δ$ T > 0 and w > 0

For free expansion of ideal gas $P_{e x t} = 0$
$W_{p v} = 0$
$q = 0$ (adiabatic process)
$Δ E = q + w$
$Δ E = 0$
$Δ E = n C_{v m} Δ T = 0$
$q = 0, Δ T = 0, w = 0$

Q. The correct option for free expansion of an ideal gas under adiabatic condition is :

q = 0, Δ T = 0 and w = 0

q = 0, Δ T < 0 and w > 0

q < 0, Δ T = 0 and w = 0

q > 0, Δ T > 0 and w > 0

For free expansion of ideal gas Pext​=0 Wpv​=0 q=0 (adiabatic process) ΔE=q+w ΔE=0 ΔE=nCvm​ΔT=0 q=0,ΔT=0,w=0

q = 0, $Δ$ T = 0 and w = 0

q = 0, $Δ$ T < 0 and w > 0

q < 0, $Δ$ T = 0 and w = 0

q > 0, $Δ$ T > 0 and w > 0

For free expansion of ideal gas $P_{e x t} = 0$
$W_{p v} = 0$
$q = 0$ (adiabatic process)
$Δ E = q + w$
$Δ E = 0$
$Δ E = n C_{v m} Δ T = 0$
$q = 0, Δ T = 0, w = 0$