The correct M-H curve for a paramagnetic material at a constant temperature (T) is represented by

Question

The correct M-H curve for a paramagnetic material at a constant temperature (T) is represented by (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since intensity of magnetisation (M) of a paramagnetic material is given by M = C (B/T) = Cμ0 (H/T) as (Cμ0/T) is constant. Then M propto H Hence, the M-H curve will be a straight line with the slope Cμ 0 (1/T).

Q. The correct $M - H$ curve for a paramagnetic material at a constant temperature $(T)$ is represented by

Since intensity of magnetisation $(M)$ of a paramagnetic material is given by
$M = C \frac{B}{T} = C μ_{0} \frac{H}{T}$ as $\frac{C μ _{0}}{T}$
is constant.
Then $M \propto H$
Hence, the $M - H$ curve will be a straight line with the
slope $C μ_{0} \frac{1}{T}$ .

Q. The correct M−H curve for a paramagnetic material at a constant temperature (T) is represented by

Since intensity of magnetisation (M) of a paramagnetic material is given by M=CTB​=Cμ0​TH​ as TCμ0​​ is constant. Then M∝H Hence, the M−H curve will be a straight line with the slope Cμ0​T1​.

Q. The correct $M - H$ curve for a paramagnetic material at a constant temperature $(T)$ is represented by

Since intensity of magnetisation $(M)$ of a paramagnetic material is given by
$M = C \frac{B}{T} = C μ_{0} \frac{H}{T}$ as $\frac{C μ _{0}}{T}$
is constant.
Then $M \propto H$
Hence, the $M - H$ curve will be a straight line with the
slope $C μ_{0} \frac{1}{T}$ .