The correct increasing order of the reactivity of halides for SN 1 reaction is:

Question

The correct increasing order of the reactivity of halides for SN 1 reaction is: (A) CH 3- CH 2- X <( CH 3)2 CH - X < CH 2= CH - CH 2- X < PhCH 2- X  (B) ( CH 3)2 CH - X < CH 3- CH 2- X < CH 2 = CH - CH 2 X < Ph CH 2- X  (C) PhCH 2- X <( CH 3)2 CH - X < CH 3- CH 2- X < CH 2= CH - CH 2- X (D)  CH 2= CH - CH 2- X < Ph - CH 2- X <( CH 3)2 CH - X < CH 3- CH 2- X

Tardigrade Admin · Accepted Answer

The relative stability of alkyl carbocation is due to inductive effect and hyperconjugation, while that of stable carbocation is due to resonance. The order is:

C H_{3} C H_{2} X < (C H_{3})_{2} C H - X < C H_{2} = C H - C H_{2} X < P h C H_{2} - X .

Q. The correct increasing order of the reactivity of halides for $S_{N} 1$ reaction is:

$C H_{3} - C H_{2} - X < (C H_{3})_{2} C H - X < C H_{2} = C H - C H_{2} - X < P h C H_{2} - X$

$(C H_{3})_{2} C H - X < C H_{3} - C H_{2} - X < C H_{2} = C H - C H_{2} X < P h C H_{2} - X$

$P h C H_{2} - X < (C H_{3})_{2} C H - X < C H_{3} - C H_{2} - X < C H_{2} = C H - C H_{2} - X$

$C H_{2} = C H - C H_{2} - X < P h - C H_{2} - X < (C H_{3})_{2} C H - X < C H_{3} - C H_{2} - X$

The relative stability of alkyl carbocation is due to inductive effect and hyperconjugation, while that of stable carbocation is due to resonance. The order is:
$C H_{3} C H_{2} X < (C H_{3})_{2} C H - X < C H_{2} = C H - C H_{2} X < P h C H_{2} - X .$

Q. The correct increasing order of the reactivity of halides for SN​1 reaction is:

CH3​−CH2​−X<(CH3​)2​CH−X<CH2​=CH−CH2​−X<PhCH2​−X

(CH3​)2​CH−X<CH3​−CH2​−X<CH2​=CH−CH2​X<PhCH2​−X

PhCH2​−X<(CH3​)2​CH−X<CH3​−CH2​−X<CH2​=CH−CH2​−X

CH2​=CH−CH2​−X<Ph−CH2​−X<(CH3​)2​CH−X<CH3​−CH2​−X