The correct increasing order of extent of hydrolysis is

Question

The correct increasing order of extent of hydrolysis is (A) CCl4 < MgCl2 < AlCl3 < SiCl4 < PCl5 (B) CCl4 < AlCl3 < MgCl2 < PCl5 < SiCl4 (C) CCl4 < SiCl4 < PCl5 < AlCl3 < MgCl2 (D) CCl4 < PCl5 < SiCl4 < AlCl3 < MgCl2

Tardigrade Admin · Accepted Answer

Among the given halides, carbon tetrachloride does not undergo hydrolysis readily due to the absence of empty

d

-orbitals. The extent of hydrolysis is proportional to the amount of positive charge present on the central atom, which is prone to attack of

H_{2} O

molecules.

CC l_{4} < M g C l_{2} < A lC l_{3} < S i C l_{4} < PC l_{5}

Q. The correct increasing order of extent of hydrolysis is

$CC l_{4} < M g C l_{2} < A lC l_{3} < S i C l_{4} < PC l_{5}$

$CC l_{4} < A lC l_{3} < M g C l_{2} < PC l_{5} < S i C l_{4}$

$CC l_{4} < S i C l_{4} < PC l_{5} < A lC l_{3} < M g C l_{2}$

$CC l_{4} < PC l_{5} < S i C l_{4} < A lC l_{3} < M g C l_{2}$

Q. The correct increasing order of extent of hydrolysis is

CCl4​<MgCl2​<AlCl3​<SiCl4​<PCl5​

CCl4​<AlCl3​<MgCl2​<PCl5​<SiCl4​

CCl4​<SiCl4​<PCl5​<AlCl3​<MgCl2​

CCl4​<PCl5​<SiCl4​<AlCl3​<MgCl2​

$CC l_{4} < M g C l_{2} < A lC l_{3} < S i C l_{4} < PC l_{5}$

$CC l_{4} < A lC l_{3} < M g C l_{2} < PC l_{5} < S i C l_{4}$

$CC l_{4} < S i C l_{4} < PC l_{5} < A lC l_{3} < M g C l_{2}$

$CC l_{4} < PC l_{5} < S i C l_{4} < A lC l_{3} < M g C l_{2}$