The correct increasing order of basic strengthamong p-nitroaniiine (I) ; p-bromoaniline (II), p-toluidine (III) is

Question

The correct increasing order of basic strengthamong p-nitroaniiine (I) ; p-bromoaniline (II), p-toluidine (III) is (A) I < II < III (B) III < II < I (C) II < I < III (D) III < I < II

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/9a882d965778e0f9d2dbb88b92c65812-.jpeg" /> -NO2 is electron withdrawing, -CH3 is electron releasing (+I effect), -Br group has -I effect but +R effect Therefore, correct order of basic strength p-Nitroaniline < p-Bromoaniline < p -Toluidine or I < II< III

Q. The correct increasing order of basic strengthamong p-nitroaniiine (I) ; p-bromoaniline (II), p-toluidine (III) is

I < II < III

III < II < I

II < I < III

III < I < II

$- N O_{2}$ is electron withdrawing, $- C H_{3}$ is electron releasing (+I effect), -Br group has -I effect but +R effect
Therefore, correct order of basic strength
$p$ -Nitroaniline $< p$ -Bromoaniline $< p$ -Toluidine or $I < II < III$

Q. The correct increasing order of basic strengthamong p-nitroaniiine (I) ; p-bromoaniline (II), p-toluidine (III) is

I < II < III

III < II < I

II < I < III

III < I < II

−NO2​ is electron withdrawing, −CH3​ is electron releasing (+I effect), -Br group has -I effect but +R effect Therefore, correct order of basic strength p-Nitroaniline <p-Bromoaniline <p -Toluidine or I<II<III

$- N O_{2}$ is electron withdrawing, $- C H_{3}$ is electron releasing (+I effect), -Br group has -I effect but +R effect
Therefore, correct order of basic strength
$p$ -Nitroaniline $< p$ -Bromoaniline $< p$ -Toluidine or $I < II < III$