The correct electronic configuration of d4 in low spin state according to Crystal Field Splitting theory is

Question

The correct electronic configuration of d4 in low spin state according to Crystal Field Splitting theory is (A)  t42g e0g  (B)  t32g e1g  (C)  t22g e2g  (D)  t12g e3g

Tardigrade Admin · Accepted Answer

In low spin state, the electrons get paired up d4: t2g4 eg0

Q. The correct electronic configuration of $d^{4}$ in low spin state according to Crystal Field Splitting theory is

$t_{2 g}^{4} e_{g}^{0}$

$t_{2 g}^{3} e_{g}^{1}$

$t_{2 g}^{2} e_{g}^{2}$

$t_{2 g}^{1} e_{g}^{3}$

In low spin state, the electrons get paired up
$d^{4} : t_{2 g}^{4} e_{g}^{0}$

Q. The correct electronic configuration of d4 in low spin state according to Crystal Field Splitting theory is

t2g4​eg0​

t2g3​eg1​

t2g2​eg2​

t2g1​eg3​