The correct decreasing order of the boiling points of compounds H2O, HF and NH3 is

Question

The correct decreasing order of the boiling points of compounds H2O, HF and NH3 is (A) HF > H2O > NH3  (B) H2O > HF > NH3  (C) NH3 >HF > H2O  (D) NH3 > H2 O > HF

Tardigrade Admin · Accepted Answer

Decreasing order of the boiling points of compounds will be,

H_{2} O > H F > N H_{3}

; due to the strength of hydrogen bonding present in given compound. So, more the hydrogen bonding, higher will be boiling point. Each water molecule can potentially form four hydrogen bonds with surrounding water molecules. Due to higher partial charge on

H

and

F

in

H F

, a hydrogen bond between

H F

molecules is stronger than that of

N H_{3}

molecules.
Hence, the

H_{2} O > H F > N H_{3}

is correct.

Q. The correct decreasing order of the boiling points of compounds $H X_{2} O, HF$ and $NH X_{3}$ is

$HF > H X_{2} O > NH X_{3}$

$H X_{2} O > HF > NH X_{3}$

$NH X_{3} > HF > H X_{2} O$

$NH X_{3} > H X_{2} O > HF$

Q. The correct decreasing order of the boiling points of compounds HX2​O,HF and NHX3​ is

HF>HX2​O>NHX3​

HX2​O>HF>NHX3​

NHX3​ >HF>HX2​O

NHX3​>HX2​ O>HF

Q. The correct decreasing order of the boiling points of compounds $H X_{2} O, HF$ and $NH X_{3}$ is

$HF > H X_{2} O > NH X_{3}$

$H X_{2} O > HF > NH X_{3}$

$NH X_{3} > HF > H X_{2} O$

$NH X_{3} > H X_{2} O > HF$