The correct decreasing order of bond angles is:

Question

The correct decreasing order of bond angles is: (A) ClF 3> PF 3> NF 3> BF 3 (B) BF 3> PF 3> NF 3> ClF 3 (C) BF 3> NF 3> PF 3> ClF 3 (D) BF 3> ClF 3> PF 3> NF 3

Tardigrade Admin · Accepted Answer

Bond angles are: BF 3-120°, NF 3-106°, PF 3-101°, ClF 3-90°

Q. The correct decreasing order of bond angles is:

$Cl F_{3} > P F_{3} > N F_{3} > B F_{3}$

$B F_{3} > P F_{3} > N F_{3} > Cl F_{3}$

$B F_{3} > N F_{3} > P F_{3} > Cl F_{3}$

$B F_{3} > Cl F_{3} > P F_{3} > N F_{3}$

Bond angles are:

$B F_{3} - 12 0^{\circ}, N F_{3} - 10 6^{\circ}, P F_{3} - 10 1^{\circ}, Cl F_{3} - 9 0^{\circ}$

Q. The correct decreasing order of bond angles is:

ClF3​>PF3​>NF3​>BF3​

BF3​>PF3​>NF3​>ClF3​

BF3​>NF3​>PF3​>ClF3​

BF3​>ClF3​>PF3​>NF3​

Bond angles are: BF3​−120∘,NF3​−106∘,PF3​−101∘,ClF3​−90∘

$Cl F_{3} > P F_{3} > N F_{3} > B F_{3}$

$B F_{3} > P F_{3} > N F_{3} > Cl F_{3}$

$B F_{3} > N F_{3} > P F_{3} > Cl F_{3}$

$B F_{3} > Cl F_{3} > P F_{3} > N F_{3}$

Bond angles are:

$B F_{3} - 12 0^{\circ}, N F_{3} - 10 6^{\circ}, P F_{3} - 10 1^{\circ}, Cl F_{3} - 9 0^{\circ}$