Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
The correct combination of three resistances 1 Ω, 2 Ω and 3 Ω to get equivalent resistance (11/5)Ω is
Q. The correct combination of three resistances
1
Ω
,
2
Ω
and
3
Ω
to get equivalent resistance
5
11
Ω
is
2879
233
Current Electricity
Report Error
A
All three are combines in parallel
23%
B
All three are combine in series
18%
C
1
Ω
and
2
Ω
in parallel and
3
Ω
is in series to both
19%
D
2
Ω
and
3
Ω
are combined in parallel and
1
Ω
is in series to both
40%
Solution:
According to option
2
Ω
and
3
Ω
are combined in a parallel combination. Hence equivalent resistance
R
′
1
=
2
1
+
3
1
=
6
5
∴
R
′
=
5
6
R
′
is combined in series to
1
Ω
∴
R
e
q
=
R
′
+
1
=
5
6
+
1
=
5
6
+
5
=
5
11
Ω