The correct arrangement for the ions in the increasing order of their radii is

Question

The correct arrangement for the ions in the increasing order of their radii is (A) Ca+2,K+,S-2 (B) Cl-,F-,S2- (C) Na+,Cl-,Ca+2 (D) Na+,Al+3,Be+2

Tardigrade Admin · Accepted Answer

Since, Ca 2+, K +, S 2- have same number of electrons so they are isoelectronic ions, as we know that, the ion having greater number of proton will be smallest in size. Thus, the increasing order of ionic radii is Ca 2+ < K +< S2-

Q. The correct arrangement for the ions in the increasing order of their radii is

$C a^{+ 2}, K^{+}, S^{- 2}$

$C l^{-}, F^{-}, S^{2 -}$

$N a^{+}, C l^{-}, C a^{+ 2}$

$N a^{+}, A l^{+ 3}, B e^{+ 2}$

Since, $C a^{2 +}, K^{+}, S^{2 -}$ have same number of electrons so they are isoelectronic ions, as we know that, the ion having greater number of proton will be smallest in size. Thus, the increasing order of ionic radii is

$C a^{2 +} < K^{+} < S^{2 -}$

Q. The correct arrangement for the ions in the increasing order of their radii is

Ca+2,K+,S−2

Cl−,F−,S2−

Na+,Cl−,Ca+2

Na+,Al+3,Be+2

Since, Ca2+,K+,S2− have same number of electrons so they are isoelectronic ions, as we know that, the ion having greater number of proton will be smallest in size. Thus, the increasing order of ionic radii is Ca2+<K+<S2−

$C a^{+ 2}, K^{+}, S^{- 2}$

$C l^{-}, F^{-}, S^{2 -}$

$N a^{+}, C l^{-}, C a^{+ 2}$

$N a^{+}, A l^{+ 3}, B e^{+ 2}$

Since, $C a^{2 +}, K^{+}, S^{2 -}$ have same number of electrons so they are isoelectronic ions, as we know that, the ion having greater number of proton will be smallest in size. Thus, the increasing order of ionic radii is

$C a^{2 +} < K^{+} < S^{2 -}$